How Do I Iterate Over The Results Of A Jquery Selector? December 22, 2023 Post a Comment When I'm trying to store all elements as objects in array (using $('a')), and then get the position of each of them, it doesn't work. years = $('a'); for(i=0;i< yearsSolution 1: Use this instead:$("a").each(function() { var pos = $(this).position(); if (pos.top > year.position().top) { // hurray } }); CopyAlso what is the value of year? I prefer to name jQuery objects like this: var $year = $("#year"); The $ helps you remember it's a jQuery object. Solution 2: You can do the following:Baca JugaDom Not Fully Loaded?Angularjs Update Service Variable Not WorkingAdding Html Text To Supersized Jquery Image Slidevar arr = [], elems = $('a'); for(var i = 0; i < elems.length; i++){ arr[i] = elems[i]; } Copy Share You may like these postsUncaught Syntaxerror: Unexpected Token < Line One JsCannot Create New Django Model Object Within Ajax Post RequestAndroid: Can't Get Javascript To Work On Webview Even With Setjavascriptenabled(true)Disable Specific Function Key Using Jquery Post a Comment for "How Do I Iterate Over The Results Of A Jquery Selector?"
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